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【纪念当年的帖子(2010)】Add Maths功课讨论区
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发表于 23-1-2010 01:09 PM
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哎呀,抱歉抱歉 ,
是要找G.P的sum
superliong 发表于 23-1-2010 01:06 PM
哈哈,很容易吧。拿你的计算机,按sin 30 =??
其实哦,你的老师也是的,都还没教TRIGO,给酱多TRIGO怎么?
sin^2 30= (sin 30)^2
你换去号码就会了。。 |
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发表于 23-1-2010 01:40 PM
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哎呀,抱歉抱歉 ,
是要找G.P的sum
superliong 发表于 23-1-2010 01:06 PM
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楼主 |
发表于 23-1-2010 02:02 PM
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楼主 |
发表于 23-1-2010 02:36 PM
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请看看这题
a. T he number x-1 , 2x-2 and 3x-1 are three consecutive terms of a germatric progression .
i. find the common ratio .
ii. Hence , calculate the sum of the first 5 terms if x-1 is the second term. |
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发表于 23-1-2010 03:23 PM
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请看看这题
a. T he number x-1 , 2x-2 and 3x-1 are three consecutive terms of a germatric progressio ...
superliong 发表于 23-1-2010 02:36 PM
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发表于 23-1-2010 03:24 PM
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回复 24# superliong
记得:每次要找r的话,一定是 Tn/Tn-1=Tn+1/Tn=... |
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发表于 23-1-2010 03:26 PM
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不如改下帖的名字。。哈哈。。已经不是dy/dx 了。。哈哈。。
改下Add Maths功课讨论区。。 |
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楼主 |
发表于 23-1-2010 04:57 PM
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修改完成,现在这里是Add Maths功课讨论区了!
请看看以下题目:
a . The second term of a G.P exceeds the third term by 4/3 and the sum of the first two terms is 8 . Find the possible values of the first three terms.
b. An email is sent to two people for the first time . The email is forwarded by each recipient to another two people for the second time . If each recipient forwards the email to two people subsequently , how many people will receive the email when it is forwarded for 10 times ?
c. The first three terms of an A.G progression are 1 , x and y while the first three terms of a G.P are 1 , y and x where x not equal y no equal 1 . Find the values of x and y .
P.S : 这题有AP和GP,请告诉我在这里AP和GP有什么共同点? |
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发表于 23-1-2010 05:10 PM
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本帖最后由 walrein_lim88 于 23-1-2010 05:48 PM 编辑
修改完成,现在这里是Add Maths功课讨论区了!
请看看以下题目:
a . The second term of a G.P exceeds ...
superliong 发表于 23-1-2010 04:57 PM
Note最后第二行,=6(is from eq 2) |
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发表于 23-1-2010 05:31 PM
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本帖最后由 walrein_lim88 于 23-1-2010 06:04 PM 编辑
修改完成,现在这里是Add Maths功课讨论区了!
请看看以下题目:
a . The second term of a G.P exceeds ...
superliong 发表于 23-1-2010 04:57 PM
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楼主 |
发表于 23-1-2010 05:42 PM
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walrein_lim88 发表于 23-1-2010 05:31 PM
谢谢,其实这个题目我不太听得懂,以为是 T1=2
T2=4
T3=8
a=2 r= 2 呢! |
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发表于 23-1-2010 05:42 PM
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修改完成,现在这里是Add Maths功课讨论区了!
请看看以下题目:
a . The second term of a G.P exceeds ...
superliong 发表于 23-1-2010 04:57 PM
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楼主 |
发表于 23-1-2010 05:49 PM
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刚刚查了书本后面的答案,是2046 people @。@ |
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发表于 23-1-2010 05:54 PM
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刚刚查了书本后面的答案,是2046 people @。@
superliong 发表于 23-1-2010 05:49 PM
哦。是吗??等下,我再CHECK下。。 |
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发表于 23-1-2010 06:05 PM
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本帖最后由 walrein_lim88 于 23-1-2010 06:06 PM 编辑
我之前想错了:
我以为第一次收到的人会在第三次FORWARD的
我以为:
第一次FORWARD给第二次, 第二次FORWARD给第三次+第一次又再FORWARD, 第三次再FORWARD+第二次又FORWARD。。。。。
所以,根据你的答案,那么
第一次的只是FORWARD给第二次,第二次FORWARD给第三次,酱只
对不起,想错了。。 |
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楼主 |
发表于 23-1-2010 09:19 PM
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回复 35# walrein_lim88
没关系,
至少帮了我一个大忙! |
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楼主 |
发表于 24-1-2010 09:15 PM
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又来一个难题
In a cell culture , each healty cell can reproduce two new cells per minute . If there 5000 cells in a dish , how many cells are there in 10 minutes ?
(Assuming that each cell can only reproduce once in that 10 minutes) |
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发表于 24-1-2010 09:21 PM
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本帖最后由 walrein_lim88 于 24-1-2010 09:30 PM 编辑
又来一个难题
In a cell culture , each healty cell can reproduce two new cells per minute . If there ...
superliong 发表于 24-1-2010 09:15 PM
忘了5000,对不起。。。
10230000+5000=10235000 |
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发表于 24-1-2010 09:29 PM
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又来一个难题
又来一个难题
In a cell culture , each healty cell can reproduce two new cells perminute . If there 5000 cells in a dish , how many cells are there in 10minutes ?
(Assuming that each cell can only reproduce once in that 10 minutes)
a = 10000, r = 2
5000 + S10 = 10235000 |
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楼主 |
发表于 25-1-2010 06:32 AM
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謝謝,
每次有一大堆英文字的都看不懂 |
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